6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2

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6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150

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Find the exact value of the following. a. cos 315 degrees. b . sin 240 degrees. c. cot 315 degrees. d. csc 225 degrees.

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SOLVED: -cos 30^∘=(√(3))/(2) -cos 60^∘=(1)/(2) -cos 90^∘=0 -cos 120^∘=(180^∘ -60^∘)=-cos 60^∘=-(1)/(2) -cos 180^∘=cos(180^∘-80^∘)=-cos 30^∘=(-√(3))/(2) -cos 180^∘=cos(180^∘-0^∘)=-cos 60^∘=-(1)/(2) -cos 210^∘=cos(180^∘+30^∘)=-30